∴BG=4,AG=2
∴S△AGB=4
∵S right angle AEOC=S right angle OFBD, and the area of quadrilateral FOCG is 2.
∴S rectangle AEOC=S rectangle OFBD= 12(S pentagon aeodb-s △ ag-s quadrilateral FOCG)+S quadrilateral focg =12 (14-2)+2 = 6.
That is k=AE? AC=6。
So choose C.