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Mathematics secondary root exercise
(1) (the root of 2-the square root of 6) 2

= [root number 2(2- root number 3)]?

= 2 * (root number 3 of 2)?

=2*(4-4 radical 3+3)

= 14-8 root number 3

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(2) (root number 18- root number 3) No.2.

=(3 radical number 2- radical number 3) radical number 2

= radical number 2*(3 radical number 2- radical number 3)÷2

= 2 (the square root of 6-6)

= the square root of 3-2 6.

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(3)(3 roots 12-2 roots 1/3+ roots 48)÷2 roots 3

=(6 roots 3-2/3 roots 3+4 roots 3)÷(2 roots 3)

= ( 10-2/3) ÷ 2

=5-3 1

=4 2/3

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(4)(2+ radical number 3)(3- radical number 3)

=6 -2 root number 3 +3 root number 3 -3

=3+ root number 3

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(5) (root number x+ root number x- 1) (root number x- root number x- 1)

= (root x)? -[root number (x- 1)]?

=x - (x- 1)

= 1

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(6) (square root of 6+root sign 12) 2- (root sign 12-6 square root) 2

= [(square root of 6+root number 12)+ (square root of root number 12-6)] * [(square root of 6+root number/square root of kloc-0/2-6)]]

Root sign12 * =2 (square root of 6 of 2)

Root number 2 of =24