∫OM is the bisector of ∞∠AOC.
∴∠AOM=( 1/2)∠AOC=75
∴∠MOB=∠AOB-∠AOM=90 -75 = 15
∵ON is the bisector of∝∠ ∝∠BOC.
∴∠BON=( 1/2)∠BOC=30
∴∠MON=∠MOB+∠BON=45
⑵∠MON=α/2
(3) ∠ mon is related to α and has nothing to do with β.
∠∠AOC =∠AOB+∠BOC =α+β
∫OM is the bisector of ∞∠AOC.
∴∠aom=( 1/2)∠aoc=(α/2)+(β/2)
∴∠mob=∠aob-∠aom=α-[(α/2)+(β/2)]=(α/2)-(β/2)
∵ON is the bisector of∝∠ ∝∠BOC.
∴∠BON=( 1/2)∠BOC=β/2
∴∠mon=∠mob+∠bon=(α/2)-(β/2)+(β/2)=α/2