Solution: 10/x= 10/2x+20.
The solution is x=4.
A: The speed of cycling students is 4 kilometers per minute.
2. If the processing capacity of robot B is x per hour, the processing capacity of robot A is x+30.
Solution: 900/(x+30)=600/x
The solution is x=60.
A: Robot A carries 90 pieces per hour, and Robot B carries 60 pieces per hour.
3. Let the speed of A be x, then the speed of B is (4/3) x..
Solution: 6/x+20= 10/(4/3x)
Solution: x=0.075
A: A is 0.075km per minute, and B is 0. 1 km per minute.
4. Let Li Qiang's hourly inventory be X.
Solution: I know that Zhang Ming's hourly inventory is 1/8.
( 1/8+x)* 1= 1/2
The solution is x=3/8.
A: It takes Li Qiang 8/3 hours to complete the inventory.