(2)

1/(√2+ 1)=√2- 1

1/(√3+√2)=√3-√2

...

1/(√ 1235+√ 1234=√ 1235-√ 1234

Original formula = (√ 2-1+√ 3-√ 2+√ 4-√ 3+...+√1235/234) (√1235+0).

=(√ 1235- 1)(√ 1235+ 1)

=(√ 1235)? - 1

= 1235- 1= 1234

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