There is a set of numbers, and the last number is 65438+ 0/3 of the previous number plus 3. If t is the first number, find the ratio of the second number to the first number.

If the first number is t, the second number is t/3+3.

The second number is more than the first number.

(t/3+3):t

=(t/3+9/3)/t

=[(t+9)/3]/t

=(t+9)/3t

It's C.