The absolute value of 1 ∫(ax-2y-4) and the root sign (2x+4) are reciprocal.
∴(ax-2y-4) Absolute value+radical sign (2x+4)=0.
The absolute value of ∵(ax-2y-4) is ≥0, and the root sign (2x+4) is ≥ 0.
∴ (absolute value of ax-2y-4) =0, and the root sign (2x+4)=0.
X=-2
Because x and y are reciprocal.
∴y=2
∴a*-2-2*4=0
∴a=-4
2.y=√ 1-2x+√(x- 1)? +√2x- 1,
It can be noted that √ 1-2x and √2x- 1,
√2x- 1=√ -( 1-2x)
So √ 1-2x and √2x- 1 are reciprocal.
(The opposite number is either positive, negative or zero. It can't be positive, so it's all zero. )
So 1-2x=0 and X= 1/2.
Substituting X= 1/2 into the original formula, you can get Y= 1/2.
So the arithmetic square root of X+Y = 1.
3.
a- 1=0,ab-2=0
a= 1,ab=2
So b=2 and a=2.
Then the original formula =11* 2+1/2 * 3+1/3 * 4+...+1/2010 * 20/kloc-.
= 1- 1/2+ 1/2- 1/3+ 1/3- 1/4+……+ 1/20 10- 1/20 1 1
= 1- 1/20 1 1
=20 10/20 1 1
I am exhausted. . . . .