So the equation is
√((x-0)^2+(y+2)^2)+√((x-0)^2+(y-2)^2)= √((3/2)^2+(9/2)^2)+√((3/2)^2+( 1/2)^2)
Square, shift term, quadratic, elliptic equation is:
5x? + 3y? = 30
Or standard x? /6 + y? / 10 = 1