Solution: let A (n) = A 1 * q (n- 1), then s (n) = a1(1-q). Find one (n-).

Substituting A(n+ 1) and s(n+ 1) into the original inequality, it is simplified as:

q^(n-2)*( 1-q)<； =0.

1. When q; 0. So q (n-2) * (1-q) > 0.

That is to say, when q

2. when q>0, for any n: q (n-2) > 0, so q (n-2) * (1-q).

3. When q=0 and n=2, there is: (a3 * s1+a1* S3) = a12. A (2) * S (2) = 0。

So we need a12.

To sum up: the range of q is: q >；; = 1.