Current location - Training Enrollment Network - Mathematics courses - Exercise in every class in the sixth grade mathematics volume, page 18, question 3. The radius of the bottom of the cylinder is 2 meters high and 6 meters high. What is its surface area?
Exercise in every class in the sixth grade mathematics volume, page 18, question 3. The radius of the bottom of the cylinder is 2 meters high and 6 meters high. What is its surface area?
In addition to the two bottom surfaces, there is also a middle cylinder, which is rectangular after expansion. The height of this rectangle is the height of the original cylinder, and the length is the circumference of the bottom of the original cylinder, that is, 2×3. 14×2= 12.56.

So the area of the rectangle = 12.56×6=75.36.

Surface area of cylinder = area of two bottoms+rectangular area obtained by expansion.

=2×3. 14×2×2+75.36

= 100.48