According to the known condition that "the tons of raw grain stored in two granaries are equal", the raw grain stored in granary B is also X tons.

In this way, the two grain depots originally had 2x tons of grain.

The tonnage of surplus grain stored after transporting 80 tons from "80 tons shipped from Grain Depot A" is x-80.

The remaining grain storage tonnage after "B granary is transported in 130 tons" is X+ 130.

From "the tonnage of granary B is three times that of granary A at this time", it is concluded that 3(x-80)=x+ 130.

For equation 3(x-80)=x+ 130

3x-240=x+ 130 times the distribution rate expansion.

Transfer project: 3x-x=240+ 130.

So 2x=370.

The 2x=370 grain depot originally had tons of grain storage.

A: These two grain depots originally stored 370 tons of grain.