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(2qs three? The area of closed shape 8 surrounded by straight line y=0 and parabola y=20-02 is sqsq.
Substitute v=x from v=3x-x3 into x=3x-x3 to get x= 7 or x= ground.

∴ Ten areas of a closed figure surrounded by a straight line v=x and a parabola v=3x-x3.

S=∫ Tiki [x-(3x3)] dx = (di3x3? Grounding 5x5)| Grounding 7 = Grounding 6,

So the answer is: 6.

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