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20 12 national new curriculum standard liberal arts mathematics college entrance examination 17 exercises
1, because c=√3asinC-ccosA.

So according to the sine theorem,

sinC=√3sinAsinC-sinCcosA

That is 1=√3sinA-cosA.

= 2(√3/2 Sina-1/2 Xhosa)

=2 (cosine π/6 sine-sine π/6 cosine)

=2sin(A-π/6)

A=π/3

2、 1/2bcsinA=√3

bc=4

cosine theorem

b*b+c*c-bc=4

b=c=2