So according to the sine theorem,

sinC=√3sinAsinC-sinCcosA

That is 1=√3sinA-cosA.

= 2(√3/2 Sina-1/2 Xhosa)

=2 (cosine π/6 sine-sine π/6 cosine)

=2sin(A-π/6)

A=π/3

2、 1/2bcsinA=√3

bc=4

cosine theorem

b*b+c*c-bc=4

b=c=2