So according to the sine theorem,
sinC=√3sinAsinC-sinCcosA
That is 1=√3sinA-cosA.
= 2(√3/2 Sina-1/2 Xhosa)
=2 (cosine π/6 sine-sine π/6 cosine)
=2sin(A-π/6)
A=π/3
2、 1/2bcsinA=√3
bc=4
cosine theorem
b*b+c*c-bc=4
b=c=2