Dye I, you can choose from five colors, there are five choices.

Then dye M, there are 4 kinds of 5-1=.

Finally, O staining, there are 5- 1- 1=3 kinds.

In each dyeing scheme of T, M can have four different choices. One * * * is 5*4=20.

Among the 20 combinations of IM staining, O has three choices for each combination. One * * * is 20*3=60.

So the answer is 3.

If you study high school permutation and combination, it is P (5,3) = 5 * 4 * 3 = 60.