The answer reference (1) of the seventh grade mathematics textbook of Beijing Normal University Edition has 42 pages.
( 1)-2; (2)8; (3)-8(4)2; (5)0; (6)-7; (7)7; (8)- 12; (9)20.
Beijing Normal University Edition Seventh Grade Mathematics Textbook Answer Reference (2) Exercise 46
Solution: (1) 33.1-(-22.9)+(-10.5) = 33.1+22.9-10.5 = 56-/kloc-.
(2)(-8)-(- 15)+(-9)-(- 12)=-8+ 15-9+ 12=-8-9+ 15+ 12=- 17+27= 10;
(3) 1/2+(- 2/3)-(-4/5)+(- 1/2)= 1/2-2/3+4/5- 1/2= 1/2- 1/2-2/3+4/5=- 10/ 15+ 12/ 15=2/ 15;
(4) 10/3+(- 1 1/4)-(-5/6)+(-7/ 12)= 10/3- 1 1/4+5/6-7/ 12=40/ 12-33/ 12+ / kloc-0/0/ 12-7/ 12=(40-33+ 10-7)/ 12= 10/ 12=5/6.
The answer reference of the seventh grade mathematics textbook published by Beijing Normal University (3) Exercise 2.8
Solution: (1) 27-28+(-7)-32 = 27-18-7-32 = 27-7+(-18-32) = 20+(-50).
(2) 1/3+(- 1/5)- 1+ 2/3= 1/3+2/3+(- 1/5)+(- 1)= 1+(- 1/5)+(- 1)=- 1/5;
(3)0.5+(- 1/4)-(-2.75)+ 1/2=0.5-0.25+2.75+0.5=0.5+0.5-0.25+2.75= 1-0.25+2.75= 1+2.75-0.25=3.75-0.25=3.5;
(4)(-2/3)+(- 1/6)-(- 1/4)- 1/2=-4/6- 1/6+( 1/4- 1/2)=-5/6- 1/4=- 10/ 12-3/ 12=- 13/ 12.
problem solving
2. Solution: 20-3-10-3+2+9+3 =18 (ten thousand people).
A: Compared with September 30th,1October 7th, 65438 passenger flow increased180,000.
3. Solution: Take 40kg as the standard weight, the number of kilograms exceeding the standard weight is positive, and the number of kilograms below the standard weight is negative.
40x 10+(7+8-2.5+2+5+0- 1.5-5.5-2+2.5)? 10=(400+ 13)? 10=4 1.3 (kg).