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Math parallelogram proving problem in the second day of junior high school
Proof: ∫ parallelogram ABCD

∴ab=cd ab∑CD

AE = CF

∴BE=DF

∫AE∨CF AE = CF

∴ Quadrilateral AECF is a parallelogram

∴AF∥CE

Similarly, DE∨BF

∴ Quadrilateral EHFG is a parallelogram

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