Because BE⊥CF

So ∠BEC=∠BEF

Bei = Bei, EBF = EBC.

So △ BEC △ BEF

So CE=EF

Abdul -BDA = 90 degrees, EDC=90 degrees, Abdul -EDC = 90 degrees.

So: ∠ABD=∠ECD=∠ACF

AB=AC and ∠BAD=∠CAF.

So: △ bad △ caf

So: BD=CF=2CE

So CE= 1/2BD.