∵AB=24m,CD=8m,AB⊥CD,
∴ad=db= 12ab= 12×24= 12m.
Let OA=r, then OD=r-CD,
At Rt△AOD,
OA2=OD2+AD2, that is, r2=(r-8)2+ 122, and the solution is r= 13m.
∴OD= 13-8=5m,
In Rt△MOE, suppose ME=5m,
Then OM2=OE2+ME2, that is, 132=OE2+52, and the solution is OE= 12m.
∴DE=OE-OD= 12-5=7m>6m.
The freighter can cross the bridge smoothly.