Solution: If the length, width and height of a cuboid are a, b and c respectively, the truncated pyramid volume is1/3×1/2× ABC =1/6abc, and the remaining geometric volume is abc- 1/6abc=5/6abc.
Question 4: There is water in the triangular prism container, and the side AA 1=8. If the side AA 1B 1B is placed horizontally, and the liquid level just passes through the midpoint of AC, BC, A 1c 1, then
Analysis: When the side of triangular prism AA 1B 1B is placed horizontally, the liquid part is a quadrangular prism, the height of which is higher than that of the original triangular prism, and the length of the side AA 1 is 8.
Solution: Let the midpoint of AC and BC sides be E and F respectively, and the liquid level height is H when the bottom ABC is placed horizontally.
SABFE×8=SABC×h, and from the condition that SABFE:SABC=3:4 and the liquid volumes in the two States are equal, it can be obtained that ∴h=6.