1. The bottom is round and the side is curved.

2. Height: the distance from the vertex to the center of the bottom surface. The cones are only one day tall.

Second,

formula

Bottom area: S=πr?

Bottom circumference =πd=2πr

Volume: V=S×h÷3

s = 3×v \u h

h = 3×v \s

Third,

Cutting of the cone:

1. Crosscutting: The section is circular.

2. Vertical cutting (passing through the vertex and diameter): the cutting plane is an isosceles triangle, and the bottom of the triangle is the diameter of the bottom circle. Height is the height of the cone. The area has been increased by two isosceles triangles.

Fourth, the transformation of quantity:

A cylinder is filled with sand and poured out to form a conical sand pile. The key to implicit problem solving is to keep the volume unchanged.

Five, the relationship between cylinder and cone:

1. Equal base height: the volume of a cylinder is three times that of a cone.

The volume of a cone is 1/3 of the volume of a cylinder.

The volume of a cone is two thirds smaller than that of a cylinder.

2. Equal volume and height: the area of the circle at the bottom of the cone is three times that of the cylinder.

3. Equal volume and bottom area: the height of a cone is three times that of a cylinder.