According to the meaning of the question, on the first day, B reflexively marched 10 minutes later and met C; The next day, B traveled reflexively for 20 minutes and then met C.

Because the process of B's reflexive travel and C's meeting is a meeting problem, and the speed of B and C remains the same, the ratio of the distance between B and A from the first day to the second day and the distance between C and the second day is 10:20, that is, 1:2.

From this, it can be concluded that the ratio of the time spent by Party A and Party B from the first day to the second day is 1:2.

Let B walk x meters per minute, and the equation is: 4800/(x+40): 4800/(x-40) =1:2.

According to "the product of inner terms equals the product of outer terms", it is 2*4800/(x+40) = 4800/(x-40).

Divide both sides of the equation by 4800:2/(x+40)= 1/(x-40)

Once again, according to "the product of inner terms equals the product of outer terms", x+40 = 2*(x-40).

The equation is solved as follows: x = 120.

Therefore, the first day of meeting between Party A and Party B takes 4800/( 120+40) = 30 (minutes).

When B meets C after driving in the opposite direction 10 minutes, the distance between B and B is: 120*(30- 10) = 2400 (meters).

Because C walked (30+ 10) minutes, the distance C walked per minute was: 2400/(30+ 10) = 60 (meters).

A: The speed of C is 60 meters per minute. It should be right. Can you calculate it again?

Expect to be adopted