Solution:

(1) intersects the X axis, and the distance between two adjacent ones is π/2. It can be obtained that the minimum positive period of f(x) is T=π, and the calculation formula of the minimum positive period is T=2π/ω, ω = 2 (ω > 0);

(2) the lowest coordinate M(2π/3, -2), A=2, (a > 0);

(3) at the lowest point, ωx+φ=2*(2π/3)+φ=2kπ+3π/2, (k∈Z), and φ=2kπ+π/6, (k∈Z), and 0 < φ < π/2, then

So the analytical formula is f(x)=2sin(2x+π/6), and the solution is finished.