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Math problem: Two pliers hold a complete crab.
If each has only one crab claw, it will only be the most.

If there are only eight feet on each foot, at least count them.

Suppose each crab has only one crab pincer and 25 crabs;

If they are all four feet, * * * has 100 feet.

If everyone has 8 feet, then * * * has 200 feet.

120 feet is between 100 and 200, then 25 crabs will be established, with a maximum of 25 crabs.

Suppose each one has only eight feet, and there are 15 crabs.

If everyone has 1 crab claws, then * * has 15 crab claws.

If everyone has two crab claws, then * * * has 30 crab claws.

If 25 crabs are between 15 and 30, then 15 crabs are established, and there are at least 15 crabs.

25 at most and 15 at least.