That is 4+P/2=5. So P=2, parabolic equation y 2 = 4p.
Let the center of the circle c (a 2/4, a) and the radius r.
From the chord length equal to 4 and Pythagorean theorem, we can know that R2 = 2 2+(a 2/4) 2, R2 = 4+a 4/16.
The circular equation is (X-A 2/4) 2+(Y-A) 2 = 4+A 4/ 16.
After deformation, (-x/2+1) a 2-2 ya+(x 2+y 2-4) = 0.
Knowing the arbitrariness of A, the coefficients of the letter A in the polynomial on the left of the above formula are all 0, so
(-x/2+ 1)=0, and 2y=0, and x 2+y 2-4.
X=2, y=0, that is, the fixed-point coordinate is (2,0).