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How do you see that the triangle ABC is a right triangle, not a right triangle, so can the opposite side be more inclined?
By using the inverse theorem of Pythagorean theorem, it can be determined that this triangle must not be a right triangle.

It is known or found that three edges are 3, 3, 4,

There are three more? +3? ≠4? Therefore, it is not a right triangle, so you can't find tanB with the opposite side, adjacent side and hypotenuse.

You have to use the same angle trigonometric function relationship to find it.

Cosb = 1/9 has been found. Use sin? B+cos? B= 1

Available sinb = 4 √ 5/9

Then use sinb/cosb = tanb.

Available tanb = 4 √ 5