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Mathematics problems in the sixth grade of Beijing Normal University in the next semester (the problem of circle and cone)
The small circle is the base and the circumference is π×6×2= 12π cm.

12π cm on the Great Circle. The circumference of the great circle =π×9×2= 18π.

The ratio of the intercepted sum to the total number = 12π: 18π = 2: 3.

Therefore, the interception area = 3.14× 9× 9× 2/3 =169.56cm2.

The area of the bottom = 3.14× 6× 6 =113.04cm2.

Cone surface area =169.56+113.04 = 282.6cm2.

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