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Junior high school mathematics unary quadratic equation
The key is to master the general steps and equation characteristics of various solutions:

3x? -x- 1 = 0;

Formula method

Because a=3, b=- 1 and c=- 1.

b? -4ac = 1+ 12 = 13 > 0

So x = (1 radical 13)/6.

That is, x 1=( 1+ root number 13)/6.

X2=( 1- root number 13)/6

2(x-4)? -24=0;

Direct Kaiping method

2(x-4)? =24

(x-4)? = 12

square root

X-4 = 2 root number 3

So the root number 3 of x 1=4+2.

The root number 3 of X2=4-2

(x+3)? = 2x+5;

Factorization method:

The original equation has been sorted out

x? +4x+4=0

(x+2)? =0

x+2=0

So x 1=x2=-2.

( 1-4y)? -5=0

Direct Kaiping method

( 1-4y)? =5

square root

1-4y = root number 5

So y 1=( 1+ root number 5)/4.

Y2=( 1- radical number 5)/4