3x？ -x- 1 = 0；
Formula method
Because a=3, b=- 1 and c=- 1.
b？ -4ac = 1+ 12 = 13 > 0
So x = (1 radical 13)/6.
That is, x 1=( 1+ root number 13)/6.
X2=( 1- root number 13)/6
2(x-4)？ -24=0;
Direct Kaiping method
2(x-4)？ =24
(x-4)？ = 12
square root
X-4 = 2 root number 3
So the root number 3 of x 1=4+2.
The root number 3 of X2=4-2
(x+3)？ = 2x+5；
Factorization method:
The original equation has been sorted out
x？ +4x+4=0
(x+2)？ =0
x+2=0
So x 1=x2=-2.
( 1-4y)？ -5=0
Direct Kaiping method
( 1-4y)？ =5
square root
1-4y = root number 5
So y 1=( 1+ root number 5)/4.
Y2=( 1- radical number 5)/4