If (x- 1)/(x+3)=y, the original equation can be transformed into:

2y+ 6/y=7

Both sides of the above formula are multiplied by y:

2y？ +6=7y

2y？ -7y+6=0

(2y-3)(y-2)=0

Solution: y? =3/2 or y? =2

When will you? When =3/2, (x- 1)/(x+3)=3/2, that is, 2(x- 1)=3(x+3) and 2x-2=3x+9, the solution is: x =-/kloc-.

When will you? When =3, (x- 1)/(x+3)=2, that is, (x- 1)=2(x+3), x- 1=2x+6, then the solution is: x=-7.

The solution of the original equation is: x? =- 1 1，x？ =-7