If a three-digit number is divided by 5 and 2, the mantissa of this three-digit number is 2 or 7.
If a three-digit number is divided by 4 and greater than 3, then the mantissa of this three-digit number must be 7.
Then the sum of the first two digits of this three-digit number is 9n-2-7=9(n- 1).
There is no solution when n= 1.
When n=2, 9(n- 1)=9, including 187, 817,277,727,367,637,457,547 and 907.
When n = 3,9 (n-1) =18, this three-digit number is only1,which is 997.
Because the last two digits -3 can be divisible by 4, those that meet the requirements are187,367,547,727,907.
There are five such three digits.
Sorry, I was careless.