Question 6: Solution: Let the speed of car B be xkm/h, then the speed of car A is (2x+20) km/h. 。

1/2x+ 1/2(2x+20)= 298。

x= 192

2x+20=2 times 192+20=404.

Question 10:

Analysis: when they were separated by 36km for the first time, they walked in opposite directions and never met; The second time, 36 kilometers apart, they walked in the opposite direction and met.

Scheme 1: Scheme: From 10 to 12, Wang Li and Chen Ping traveled 36+36 = 72 (km) for 2 hours, so from 8: 00 to 10, Wang Li and Chen Ping also traveled 72km in 2 hours. Let the distance between a and b be xkm.

Solution 2: Solution: Let the distance between the two places be xkm, and when 10 am, the distance they walk is (x-36)km. The speed sum is x-36/2 km/h, noon 12, the distance they walk is (x+36)km, and the speed sum is X+36/4km/h. According to the speed sum equation, x-36/2=x+36/4, and X = 65438.

All right! I hope I can help you! o(∩_∩)o ..