First of all, because lg(x) is meaningful, it is necessary to make X greater than 0, that is, both x 1 and x2 are positive numbers, excluding item A. Then, the exponential function on the left tends to 0, and the absolute value of the logarithmic function on the right first decreases and then increases, and the minimum value is 0 at x= 1, so one of the two roots is greater than 1. Let x 1 be less than 1 and x2 be greater than 1. Substitute them into the equations respectively, and then subtract the two equations to get that log (x 1x 2) = 2 (-x2)-2 (-x 1) is less than 0, so x1x2 is less than1,so choose D.