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Several problems in mathematics
The last one is 2, and the number is.

1 2 2

12 122 2+3

12 122 1222 2+3+4

So let's see when.

2+3+...+n & lt; =2008

And 2+3+...+n+(n+ 1)>2008.

1+2+...+n & lt; =2009

n(n+ 1)/2 & lt; =2009

n(n+ 1)& lt; =40 18

n=62,62*63=3906

n=63,63*64=4032

So n=62 is satisfied.

That is, when n=62, mantissa 2 is the number n (n+1)/2-1=1952.

1953 is 1, and the rest is from February to 2008.

So it's 2.

Sum = number of1+number of 2 *2

=63+2*(2008-63)

=63+3890

=3953