How many four-digit even numbers are composed of 0, 1, 2, 3, 4 and 5? The first five digits are 1, 2, 3, 4, 5.

When the first four digits of 1 are even, the digits must be one of 0, 2 and 4.

When the unit number is 0, there are 1230, 1240, 1250, 1320, 1340, 1350 and 1420.

When the number of units is 2, there are also twelve combinations.

When the number of units is 4, there are also twelve combinations.

So there are 36 combinations of the first four-digit even number of 1.

When the four digits at the beginning of 3 are even, the digit must be one of 0, 2 and 4.

Similarly, there are 36 combinations.

When the first four digits of 5 are even, the digit must be one of 0, 2 and 4.

Similarly, there are 36 combinations.

When the four digits at the beginning of 2 are even, the single digits must be one of 0 and 4.

When the unit number is 0, there are 2 130, 2 140, 2 150, 23 10, 2340, 2350, 24 10, 2430, 2450.

When the number of units is 4, there are also 12 combinations.

So there are 12 combinations at the beginning of 2.

When the first four digits of 4 are even, similarly, there are 12 combinations.

So how many four-digit even numbers 0, 1, 2, 3, 4, 5 make up 132 combinations.

To be greater than 43 10, you must start with 4 and 5.

At the beginning of 5, everything in the last three digits of 5 is greater than 43 10 and even, so the single digits must be 0, 2 and 4.

So there are:

When the unit number is 0, there are four numbers: 1, 2, 3 and 4, and the combination of four numbers and two numbers is 5 120, 5 130, 5 140, 52 10, 5230 and 5230.

When the unit number is 2, there are four numbers: 0, 1, 3 and 4, and there are twelve combinations in the same way.

When the unit number is 4, there are four numbers: 0, 1, 2 and 3, and there are twelve combinations in the same way.

So there are 36 combinations at the beginning of five words.

At the beginning of the word 4, only 45'' and 43''' can be arranged.

When the hundredth digit is 5, that is, the random combination of the last two digits of 45'' is greater than 43 10 and even, then the digit must be 0,2.

When the unit number is 0, there are three combinations: 45 10, 4520 and 4530.

When the unit number is 2, there are three combinations: 4502, 45 12 and 4532.

When the hundredth digit is 3, that is, 43'', and it is even, then the single digit must be 0,2.

When the unit number is 0, there are two combinations of 4320 and 4350.

When the unit number is 2, there is 4352.

So, how many non-repeating numbers can consist of six numbers: 0, 1, 2, 3, 4, 5? There are 45 permutations of four-digit even numbers greater than 43 10.

0, 1, 2, 3, 4, 5, how many non-repetitive numbers can these six numbers make up? There are 132-45 = 87 combinations of four-digit even numbers not greater than 43 10.