This kind of problems can be compared by combining the intermediate method with the constructor method. We know that exponential numbers are all greater than zero, so we can compare them with intermediate quantities, such as 1, and for logarithms, we can compare them with intermediate quantities of 0. For this problem, the molecules of B and C are 1. If the denominator is used, the root number of e is twice that of e, so b is less than c, so the answer is that c is greater than a and greater than B.