When the plates of B capacitor are staggered, the capacitance C of B capacitor decreases, while the total power of the two capacitors remains unchanged and the voltage is equal, so that the charging power of B decreases and the charging power of A increases. From C=QU, it can be seen that the voltage of B plate increases, the field strength increases, and the electric field force acting on the particles increases, so the particles accelerate upward. So, A is right and D is wrong.
B, c, charged particles accelerate upward, according to Newton's second law: qu ′ d-mg = m? g2？ ②
From ① ②, u ′ = 32u is obtained.
Then the voltage between the plates becomes 32 times of the original. According to the definition formula of capacitance C=QU, the charging amount of A is 32 times of the original, and that of B is 12 times.
According to the definition formula of capacitance C=QU, the capacitance of B is 13 times, and the opposite area of B is reduced to 13. So, C is right and B is wrong.
Therefore: AC