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Mathematical problems of 0
X→0+ means that X approaches 0 from the right, that is, X >;; 0,

X→0- means that X approaches 0 from the left, which is X.

2. Let u = 1/x, lim.

= lim & ltu→+∞& gt; ue^(-u)= lim & lt; u→+∞& gt; U/e u = 0, choose B.

3. Let u = 1/x, lim.

= lim & ltu→-∞& gt; Ue (-u) =∞, choose C.

1 It can be seen that lim < x→0>;; E (- 1/x)/x does not exist. Option d