Distance from the center of the circle (1, -2) to the straight line d= radical number (R 2-(L/2) 2) = radical number (4- 1)= radical number 3.

And d=|4k+2-4|/ radical number (k 2+ 1) = radical number 3.

Therefore | 4k-2 | 2 = 3 (k 2+ 1).

16k^2- 16k+4=3k^2+3

13k^2- 16k+ 1=0

K = (16 √ 202)/26 = (8 tugeno. 5 1)/ 13

The linear equation is: y+4 = (8 √ 51) (x+3)/13.