2. Let the linear equation be: y = kx+b.
From the meaning of the question: 22tan α-11=15+9tan α, so tanα=2, so the slope k of the straight line L is 2, because the intercept of the straight line L on the X axis is -2, so 0 = 2 *(2)+b, so b=4.
3. Let the straight line equation be y=kx+4, because the straight line and the straight line y=3x+4 are symmetrical about y, so k=-3.
So the linear equation is y=-3x+4.
4. The inclination of line y=-(√3/3)x+5 is 150, so the inclination of line L is 30, so the slope of line L is √3/3. Let the equation of the straight line L be y = (√ 3/3) x+b.
(1) Because the straight line L passes through point P(3, -4), -4=(√3/3)*3+b, so b=-4-√3/3.
So the equation of the straight line L is y=(√3/3)x-4-√3.
(2) Because the intercept of the straight line L on the X axis is -2, so 0=(√3/3)*(-2)+b, so b=2√3/3.
So the equation of the straight line L is y=(√3/3)x+2√3/3.
(3) Because the intercept of the straight line L on the Y axis is 3, b=3.
So the equation of the straight line L is y=(√3/3)x+3.