Then the password must be:
(2n+ 1)^2-(2n- 1)^2
=8n
So the secret number is a multiple of 8.
1)2003÷8=250……3
So the minimum number that meets the conditions is
8×25 1=2008
2) Two consecutive even numbers can be represented as 2n and 2n+2.
(n is a positive integer)
(2n+2)^2-(2n)^2
=8n+4
It is not a multiple of 8, so it is not a secret number.
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