1. A ship carries 595 tons of oil and B ship carries 225 tons of oil. How many tons of oil must be pumped from ship B to ship A to make the oil load of ship A reach four times that of ship B? Assuming that X tons of oil is pumped from ship B, then 595+x = (225-x) × 4 595+x = 900-4x4x+x = 900-595 5x = 305x = 6 1 a: 61ton of oil must be pumped from ship B to ship A. After 30 minutes, A returned to Xizhen for official business, stayed in Xizhen for half an hour, and then went to Dongzhen. The result is 30 minutes later than B, trying to find the distance between the two towns. Solution: Suppose it takes X hours for A to set off from Xizhen to Dongzhen for the second time. Then15x =10x (0.5x3)+10 (x-0.5)15x =15+10x-515x. The distance between east and west towns is 30 kilometers. My brother is three times as old as his brother. My brother is the same age as his brother. Brother and brother are 30 years old. How old are they now? Solution: Let my brother's age be X, then multiply both sides of the equation by 3 to get 6x-90 = 90-3x-6x+4x = 90+9010x =180x =18 and substitute 30-x = 30-18. My brother is now 12 years old. Xiaohong, Xiao Li and Xiao Qiang each bought some exercise books with the same amount of money. Xiaohong bought 0.6 yuan, two less than Xiao Qiang, and Xiao Li bought 0.4 yuan, three more than Xiao Qiang. How many exercise books did Xiao Qiang buy? What is the price of each book? Answer: Suppose Xiao Qiang bought X exercise books. Then 0.6× (x-2) = 0.4× (x+3) 0.6x-1.2 = 0.4x+1.20.6x =1.2+1.20.2x = I bought 12 exercise books at the price of 0.5 yuan. There are several bags of rice in the grain depot. For the first time, more than half of the rice in stock was shipped out, and for the second time, the remaining half was shipped out in 10 bags. 200 bags were brought in for the third time, and there were 260 bags left in the grain depot. How many bags of rice are there? Solution: If the original rice bag of grain depot is x=240, then X = 240 A: the original rice bag of grain depot is 240. 6. Li Gang rode a bicycle from place A to place B, first riding an uphill road and then riding a flat road. After he arrived in B, he immediately went back to A, and it took him three hours to go back and forth. Li Gang rode 6 kilometers more on the flat road than on the uphill road. Downhill is 3 kilometers more than flat road. It is known that the first hour is 5 kilometers less than the second hour (the second hour is an uphill and a flat road), and the second hour is 3 kilometers less than the third hour. So: (1) How many minutes did Li Gang spend on the uphill road? (2) How many minutes did it take to go down the mountain? (3) How many kilometers is the distance between Party A and Party B? Solution: (1) Because the uphill road is less than 6 kilometers per hour, and the first hour is less than the second hour, the uphill road takes * * * time: (2) Suppose the third hour is x hours for the paved road and 1-x hours for the downhill road. So 6x+(6+3) (1-x) = 86x+9 (1-x) = 86x+9-9x = 89-3x = 83x = 9-8, so downhill * * is 60-20=40 (minutes So: if both sides of the equation are multiplied by 6, then 7x = 4 (x+9) 7x = 4x+363x = 36x =12 (hour) (km a: 70 minutes uphill, 40 minutes downhill * *). The distance between Party A and Party B is 24.5km) 595+x = (225-x) × 415x =10x (0.5× 3)+10 (x-0.5) 6x-90 = 90-3x-x0.6. = 40% 654402+0.4χ= 7.6 0.4χ-2.8 = 7.6χ÷( 1-0.24)= 1. 15 0.375χ+0.25χ= 105 0.5χ+ 15 = 40χ-0.2 5χ= 18χ+0.3χ。 ( 10+X)(500-20x)= 6000 X/9+X/ 12)x8 = X+200(X/9+X/ 12)8 = X+200 1:。 It is known that the master needs 6 hours to process these parts alone, and the apprentice needs 10 hours. How many parts are there in this batch? Let the total amount be x, the master will complete X/6 of the total amount in one hour, and the apprentice will complete X/ 10 of the total amount in one hour. The master finishes more than the apprentice every hour1/6-110 = x/15. Two people need to cooperate1(1/6+1) =10. The equation should be (x/6-x/10)/(1/6+110) = 30x/15/(4/15). The original basketball is 30*7/(7+3)=2 1, and the original volleyball is 30-2 1=9. Suppose you should buy X volleyballs (9+x)/(30+x) = 40% 9+x =12+0.4x0.6x Suppose A has X people, B You have11/9 (x-1/4x) = (100-x+1/4x) 65438+6 15 students, who are known to be sixth graders. How many students are there in each of these three grades? If there are X students in grade six, 5X/2/2=5/4X students in grade five and 7X/3/2=7/6X students in grade four. X=645/4x+7/6x = 6154112x = 615x =180 There are 5/4X=225 students in Grade Five and 7/6x = 2 in Grade Four. Then the original b:1245-x =1245-645 = 600 people. That is, A has 645 people and B has 600 people. Young Pioneers gave their love, and the fourth and fifth grades donated 896 yuan. The fifth grade donated less 82 yuan than the sixth grade, and the sixth grade donated more 128 yuan. How much do you donate for each of the three grades? Suppose that the fifth grade donates X yuan, the sixth grade donates x+82, and the fourth grade donates 896-XX+82-(896-X) =128x = 4717: In the fruit market, the price of apples is more expensive than that of pears in 0.7 yuan, which is 1.25 times that of pears. What are the prices of apples and pears respectively? Let the price of apples be X Yuan X/(x-0.7) = 1 .25x = 3.5x-0.7 = 2.88: there are three kinds of packaging for a beverage, and 1 medium bottle is 20 cents cheaper than 2 small bottles, and 1 large bottle is more expensive than 1 medium bottle. Set the unit price of small bottle to X angle, medium bottle to 2x-2 angle and large bottle to 3x+2 angle. X+2x-2+3x+2 = 966x = 96x =162x-2 = 32-2 = 303x+2 = 48+2 = 509: The freshmen have a meeting in the conference room, and there are 12 people in each row, so there is/kloc. There are 14 people in each row, and the rest 1 people sit in a row alone. How many rows of seats are there in this conference room? There are x rows of seats and y students. List the equations:12x+1= y (1)14x-13 = y (2)-(1): 2x = 24x = ) 10: The speed of the car is 70km/h and the speed of the van is 60km/h.. The two cars are driving in the same direction, the distance is 185.2km, with the car in front and the van behind. It takes 2.5 hours for the truck to leave. 3.7 hours after the transfer, how many kilometers are the two cars apart? It takes 2.5+3.7 hours for a van, so it takes (2.5+3.7) * 3.7 hours for a 60 km car. Ok, there is a 3.7*70km car 185.2km ahead. If the distance between the two cars is X km, then 3.7 * 70+185.2 = x+(2.5+3.7) * 60444.5 = x+372x = 444.5. Train from the camp at a speed of 6 kilometers per hour. After 16 km, the correspondent chased them by bike at 14 km/h. How many hours can he catch up? How many kilometers to the camp when we catch up? If you set x hours to catch up, your classmates will travel 6x kilometers in these x hours. Correspondent 14x km correspondent 16km has many lines, so14x =16+6x14x-6x =16x = 2, so there are two. Railway distance between the two cities1500km. The two trains start from two cities and run in opposite directions. The average speed of the local train is 82 kilometers per hour, and the average speed of the express train is 106 kilometers. After the express train is 90 kilometers, the local train will leave again. How many hours after the local train leaves, will you meet the express train on the way? Let x hours satisfy 106x+90+82x= 1500, and x=7.5 is obtained.

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