This problem can be thought of as follows: the height of the remaining part of the inverted space-time is 5 cm, and the volume of this 5 cm is equal to the volume of the inverted space-time part. Therefore, a beverage bottle with a volume of 500 cubic centimeters can be regarded as a cylindrical container with a height of (15+5) cm. So now the volume of the beverage in the bottle accounts for 15/( 15+5)=3/4, which is calculated to be 500 ×3/4=375 (cubic centimeter).