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What are the probabilities of one mistake and two mistakes in the four connection questions?
First of all, if you look at it this way, the connection questions are actually corresponding. Now there are four questions, assuming they are A, B, C and D. What they actually need to connect should be A 1, B 1, C 1, D 1, so one is wrong and the other is definitely wrong, because of the connection questions.

The probability of two mistakes should be: choose two mistakes in four lanes and the other two are right. So the answer is: C42/A44=6/24= 1/4.