Assume that X products are produced in each batch, and the production preparation cost of each product is 800/x.

The daily storage fee is x/8* 1=x/8.

∴ The sum of the two expenses of each product is f (x) = 800/x+x/8 = (6400+x 2)/(8x).

Let f' (x) = (8X2-6400 * 8)/(64x2) = 0 = > x = 80.

When x=80, f(x) takes the minimum value of 20.

Option b

Question 8:

AB=2√2，s(⊿abc)= 1/2*ab*h=√2h=2==>； h=√2

There are four points with a distance of √2 from the image with function Y = x 2 to the straight line AB.

That is, two straight lines x+y-2=0, x+y-4=0 (parallel to AB and on both sides, the distance to AB is √2) and Y = X 2 images have two intersections, so they are not calculated specifically, and you can calculate them yourself if you are interested.

So, choose one.