Solution: Let BC and AD intersect at F, and the vertical intersection F is that AB intersects at G, and the known angle DAE = 60°∴ angle fag = 90° = 60°∴af = 2fg.

Ag = √ 3fg: Angle b = 45°∴ Triangle BFG is an isosceles right triangle ∴ BG = FG: AB = 8 ∴ AB = BG+AG = (1+√ 3) FG = 8.

FG=8/( 1+√3)∵AB vertical AC ∴fg// AC ∴ Ag = the height of the triangle ACG on one side of the triangle ACG, that is, the overlapping area = AC * FG/2 = 10 * 8/[