2^b=5

2^c=30

From 3*5*2=30

2^a*2^b*2=2^c

2^(a+b+ 1)=2^c

a+b+ 1 = c(2)x+ 1+y(x+ 1)= 6

(x+ 1)(y+ 1)=6

1.x=2 y= 1

2. x =1y = 2 (3) the square of a-the square of b-the square of c -—2bc.

=a^2-(b^2+c^2+2bc)

=a^2-(b+c)^2

=(a-b-c)(a+b+c)

Because the sum of two sides is greater than the third side.

Therefore, a < b+c

, that is, A-B-C < 0

Then the value of the algebraic expression is less than 0.