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Seventh, the pursuit of mathematics
Follow-up question: A rides a bike from A to B at a speed of 16 km per hour. An hour later, B also rode his bike from A to B at a speed of 20 kilometers per hour. As a result, they both arrived at B at the same time. How many kilometers is it between A and B?

Speed difference: 20- 10= 10 (km) Distance difference: 10* 1= 10 (km) Catch-up time:10/1.

Yours may be two questions with the same idea, and the formula is as follows:

20-16 = 4km16 *1=16km.

16/4=4 (hours) 4*20=80 (kilometers)

Meeting question: 1. Both A and B are running at a constant speed on a 400-meter-long circular runway. They both start from the same place and walk in the same direction at the same time. The speed of A is 100 m/min, and the speed of B is three times that of A. How long did it take to meet for the second time?

The pursuit distance is 800 meters, and the pursuit time (note: the first encounter at the beginning is not counted)

T = 800/(3/2 *100-100) =16 (minutes)

16 minutes later, we met again.

Ring track: A male and a female athlete practice long-distance running on the ring track. Male athletes are faster than female athletes. If they start from the same starting point in opposite directions at the same time, they meet every 25 seconds. Now they are starting from the same starting point and heading in the same direction at the same time. Male athletes caught up with female athletes in 15 minutes, running 16 laps more than female athletes. How many laps did the female athlete run?

Let the speed of male athletes be x, the speed of female athletes be y, and the length of the circular runway be l.

(X+Y)*25=L

(X-Y)* 15*60= 16L

Solve the equation and get the speed Y = L/90m/s of female athletes.

In the calculation, the running distance of female athlete 15 minutes is Y* 15*60= 10L.

That is, the female athlete ran 10 lap.