qE=ma？ ①
Let the velocity of particles leaving the electric field into the magnetic field be v, the component velocity in the Y-axis direction be vy, and the movement time of particles in the electric field be t, then there are:
vy=at②
l=mv02qE=v0t③
v=v02+vy2④
According to the formula 1234, v=2v0⑤.
sinθ=v0v⑥
According to ⑤ ⑤ formula: sinθ=22⑦.
It can be obtained from formula ⑦: θ = 45 ⑧.
(2) After the particles enter the magnetic field, they move in a circle under the Lorentz force, as shown in the answer sheet.
The particle do uniform circular motion in a magnetic field, and that centripetal force provided by Lorentz force include:
qvB=mv2R
So there is a particle motion orbit radius: r = mvqb.
It can be seen from the answer diagram that if charged particles can pass through the magnetic field region without returning to the electric field, then the width d of the magnetic field should satisfy:
d≤R( 1+cosθ)？ ⑩
The solution from participation: dmax = (1+2) mv0qb … (13)
A: (1) The velocity v of charged particles entering the magnetic field is praised and trampled. What's your comment on this answer? Put away your comments and recommend lawyer services: If your problem is not solved, please describe your problem in detail and provide free professional consultation through Baidu Legal Pro. Other similar problems 2011-02-21. There are a uniform electric field with a field strength of E and a uniform magnetic field with a magnetic induction strength of B in the coordinate space, and the Y axis is the interface of the two fields. 182065438. There is a uniform electric field in the space where Y > 0 and a uniform magnetic field in the space where Y < 0. The magnetic field direction is 2620 12- 10-03, there is a uniform electric field in the space with Y > 0, and there is a uniform magnetic field in the space with Y < 0, and the magnetic field direction is 6543. In the plane rectangular coordinate system space, there is a uniform electric field with a field strength of E and a uniform magnetic field with a magnetic induction strength of B, and the Y axis is the division of the two fields of 22012-0/-21. As shown in the figure, there is a uniform electric field and a uniform magnetic field with a field strength of E in space, the Y axis is the interface of the two fields, and the dotted line in the figure is the right boundary of the magnetic field area. As shown in the figure, the existing 620 16-0 1-24 has a uniform electric field with a field strength of E in the space with Y > 0, and a uniform magnetic field of 22012-/kloc-0-09 in the space with Y > 0. As shown in the figure, there is a uniform electric field in the space where Y > 0, and the field strength is negative along the Y axis. In the space where y < 0, there is a uniform magnetic field with the direction perpendicular to x3. & gt recommended for you: F.context('cmsRight', [{'URL':'/d01373f082025aaf511aa256e9edab64034f1a07? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId':'A24KA00562 '，}，{ ' URL ':/s？ word = % E6 % AC % A7 % E6 % B4 % B2 % E6 % 9D % AF & sa = searchpromo _ ozb _ zhidao _ tuijian '，' src ':'/3 BF 33 a 87 e 950352 AAF 5 df 4954 143 fbf2b 2 1 18 b6b？ x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId ':' '，}])； The price of electric cars has dropped many times. Is the quality guaranteed? What impact will the "network toilet" have? Is Huaqiang North's second-hand mobile phone reliable? Why is the cost of cancer treatment getting higher and higher? I recommend f.context ('recbrand', [{"img": "\/86D6277F9E2F07083523F69DFB 24B 899A901F20d? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto "，" url":"/hm.js？ 6859 ce 5a af 00 FB 00387 e 6434 E4 FCC 925 "； var s = document . getelementsbytagname(" script ")[0]； s.parentNode.insertBefore(hm，s)； })(); window . TT = 1720098 152；