E cannot satisfy the polynomial equation with algebraic number as coefficient or exponent, that is, C0+C 1 EK1+C2EK2+...+CNEKN ≠ 0, where C0, C1,..., CN (not all zeros), K/KLOC-0. The transcendence of e is easy to prove. Judging from the famous Euler formula E iπ+ 1 = 0, π is a transcendental number. Otherwise, if π is an algebraic number, then π is also an algebraic number, so eπ+1≠ 0 contradicts Euler's formula. So π is a transcendental number. So π+3 has transcendence.