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Mathematical straight lines and circles in college entrance examination
... o point is the origin of coordinates! Then OE should pass the (0,0) point. Why didn't the OE equation calculated by your classmate pass the (0,0) point?

The problem is not difficult, tell yourself how to solve it!

First, write the equations of AC, AB, BP and CP, and calculate the coordinates of the intersection E of AC and BP. Similarly, calculate the coordinates of f, and point O is (0,0). Through two points, we can get the equations of OE and of.

See if you typed the question wrong again.

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AP:y =(-a/c)x+a; AB:y =(-a/b)x+a;

BP:y =(-p/b)x+p; CP:y =(-p/c)x+p;

Coordinates of point e

(-a/c)x+a =(-p/b)x+p x(E)= BC(p-a)/(CP-ab);

Bring X into Y (E) = AP (C-B)/(CP-AB);

OE:y =(AP/BC)(c-b)/(p-a)x; simplify

( 1/b- 1/c)x+( 1/p- 1/a)y = 0

Similarly, x (f) = BC (P-A)/(Pb-AC);

y(F)= AP(b-c)/(p B- AC);

OF:y =(AP/BC)(b-c)/(p-a)x; Simplified

( 1/b- 1/c)x-( 1/p- 1/a)y = 0。

From this problem, we can see that k(OE)=-k(OF).

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Off-topic: Math problems must be studied by yourself. You will make progress, and the sense of accomplishment after you make it is something you can't feel now.