1) point p brings P(m, a) into Y = AX 2 in the first quadrant (I think it should be in the form of quadratic density, otherwise the condition of p in the first quadrant is redundant and parabolic), and m 2 =1) p is in the first quadrant, so m= 1.

2) The coordinate of the intersection point A of the straight line y=kx+b and the X axis is (0, b), then OA=b because b=2a and OA=2a.

The coordinate of point P is (1, a), so OP2 = (1-0) 2+(a-0) 2pa2 = (1-0) 2+(a-b) 2.

B=2a is brought into OP2 =1+a2pa2 =1+a2oa2 = 4a2, so the assumption is not valid.